Поскольку вы использовали sh
, а не bash
, то echo
команда в sh
не имеет опции -e
. С sh
manpage:
echo [-n] args...
Print the arguments on the standard output, separated by spaces.
Unless the -n option is present, a newline is output following the
arguments.
И это тоже не имеет \e
:
If any of the following sequences of characters is encountered
during output, the sequence is not output. Instead, the specified
action is performed:
\b A backspace character is output.
\c Subsequent output is suppressed. This is normally used at
the end of the last argument to suppress the trailing new‐
line that echo would otherwise output.
\f Output a form feed.
\n Output a newline character.
\r Output a carriage return.
\t Output a (horizontal) tab character.
\v Output a vertical tab.
\0digits
Output the character whose value is given by zero to three
octal digits. If there are zero digits, a nul character
is output.
\\ Output a backslash.
All other backslash sequences elicit undefined behaviour.
echo
/bin/sh
dash